![A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm . An object is placed at 6 cm from the objective lens. A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm . An object is placed at 6 cm from the objective lens.](https://haygot.s3.amazonaws.com/questions/1680735_1591611_ans_d7c08a617cec4f7fb63fdfb24a7231d0.jpg)
A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm . An object is placed at 6 cm from the objective lens.
![Find the maximum magnifying power of a compound microscope having a 25 diopter lens as the objec... - YouTube Find the maximum magnifying power of a compound microscope having a 25 diopter lens as the objec... - YouTube](https://i.ytimg.com/vi/e7knmmm_Ks4/maxresdefault.jpg)
Find the maximum magnifying power of a compound microscope having a 25 diopter lens as the objec... - YouTube
Lenses of power 3D and - 5D are combined to from a compound lens.An object is placed at a distance of 50 cm from this lens. The position of its image will
What is the formula to find the magnification of compound microscope by the magnification of eye piece and objective lens? - Quora
![optics - How is focal length defined for a two-lens system, separated by a distance $d$? - Physics Stack Exchange optics - How is focal length defined for a two-lens system, separated by a distance $d$? - Physics Stack Exchange](https://i.stack.imgur.com/fwrwB.png)
optics - How is focal length defined for a two-lens system, separated by a distance $d$? - Physics Stack Exchange
![SOLVED: A compound lens system consists of two converging lenses, one at x=−20.0cmx=−20.0cm with focal length f1=+10.0cmf1=+10.0cm, and the other at x=+20.0cmx=+20.0cm with focal length f2=+8.00cmf2=+8.00cm. (Figure 1)An object 1.001.00 centimeter tall SOLVED: A compound lens system consists of two converging lenses, one at x=−20.0cmx=−20.0cm with focal length f1=+10.0cmf1=+10.0cm, and the other at x=+20.0cmx=+20.0cm with focal length f2=+8.00cmf2=+8.00cm. (Figure 1)An object 1.001.00 centimeter tall](https://cdn.numerade.com/ask_previews/446e3fa1-4491-4795-8add-4fb51f65738e_large.jpg)